Base | Representation |
---|---|
bin | 111010010111110111101… |
… | …000100100111011000001 |
3 | 112012111000111211120222102 |
4 | 322113313220210323001 |
5 | 1011210230412042023 |
6 | 12310443134520145 |
7 | 562545134510426 |
oct | 72276750447301 |
9 | 15174014746872 |
10 | 4011359096513 |
11 | 13072316a7a3a |
12 | 549518066055 |
13 | 231367242812 |
14 | dc217ba7d4d |
15 | 6e52832d628 |
hex | 3a5f7a24ec1 |
4011359096513 has 2 divisors, whose sum is σ = 4011359096514. Its totient is φ = 4011359096512.
The previous prime is 4011359096477. The next prime is 4011359096539. The reversal of 4011359096513 is 3156909531104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2219527876864 + 1791831219649 = 1489808^2 + 1338593^2 .
It is a cyclic number.
It is not a de Polignac number, because 4011359096513 - 28 = 4011359096257 is a prime.
It is not a weakly prime, because it can be changed into another prime (4011359096113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2005679548256 + 2005679548257.
It is an arithmetic number, because the mean of its divisors is an integer number (2005679548257).
Almost surely, 24011359096513 is an apocalyptic number.
It is an amenable number.
4011359096513 is a deficient number, since it is larger than the sum of its proper divisors (1).
4011359096513 is an equidigital number, since it uses as much as digits as its factorization.
4011359096513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 437400, while the sum is 47.
The spelling of 4011359096513 in words is "four trillion, eleven billion, three hundred fifty-nine million, ninety-six thousand, five hundred thirteen".
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