Base | Representation |
---|---|
bin | 111010010111111010010… |
… | …000111100000001001001 |
3 | 112012111010120212212112100 |
4 | 322113322100330001021 |
5 | 1011210323211400210 |
6 | 12310451352504013 |
7 | 562546211606331 |
oct | 72277220740111 |
9 | 15174116785470 |
10 | 4011403231305 |
11 | 1307254602078 |
12 | 54952a9ab009 |
13 | 231373426392 |
14 | dc21d9b60c1 |
15 | 6e52c14a5c0 |
hex | 3a5fa43c049 |
4011403231305 has 48 divisors (see below), whose sum is σ = 7015847215104. Its totient is φ = 2120146358400.
The previous prime is 4011403231271. The next prime is 4011403231307. The reversal of 4011403231305 is 5031323041104.
It is a happy number.
It is not a de Polignac number, because 4011403231305 - 27 = 4011403231177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4011403231307) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4611880 + ... + 5412230.
It is an arithmetic number, because the mean of its divisors is an integer number (146163483648).
Almost surely, 24011403231305 is an apocalyptic number.
4011403231305 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
It is an amenable number.
4011403231305 is a deficient number, since it is larger than the sum of its proper divisors (3004443983799).
4011403231305 is a wasteful number, since it uses less digits than its factorization.
4011403231305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 801366 (or 801363 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 4011403231305 its reverse (5031323041104), we get a palindrome (9042726272409).
The spelling of 4011403231305 in words is "four trillion, eleven billion, four hundred three million, two hundred thirty-one thousand, three hundred five".
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