Base | Representation |
---|---|
bin | 10010001111011111101111… |
… | …10101010110010101001101 |
3 | 12021000221110101122022201202 |
4 | 21013233313311112111031 |
5 | 20224220212012103142 |
6 | 221152302223515245 |
7 | 11310126365013143 |
oct | 1107576765262515 |
9 | 167027411568652 |
10 | 40114857534797 |
11 | 11866685316a51 |
12 | 45ba640758b25 |
13 | 194ca79261ac6 |
14 | 9c97d8877593 |
15 | 49872d4c9032 |
hex | 247bf7d5654d |
40114857534797 has 2 divisors, whose sum is σ = 40114857534798. Its totient is φ = 40114857534796.
The previous prime is 40114857534721. The next prime is 40114857534827. The reversal of 40114857534797 is 79743575841104.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39985526674921 + 129330859876 = 6323411^2 + 359626^2 .
It is a cyclic number.
It is not a de Polignac number, because 40114857534797 - 218 = 40114857272653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40114857534197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20057428767398 + 20057428767399.
It is an arithmetic number, because the mean of its divisors is an integer number (20057428767399).
Almost surely, 240114857534797 is an apocalyptic number.
It is an amenable number.
40114857534797 is a deficient number, since it is larger than the sum of its proper divisors (1).
40114857534797 is an equidigital number, since it uses as much as digits as its factorization.
40114857534797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 118540800, while the sum is 65.
The spelling of 40114857534797 in words is "forty trillion, one hundred fourteen billion, eight hundred fifty-seven million, five hundred thirty-four thousand, seven hundred ninety-seven".
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