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40120000411 = 192111578969
BaseRepresentation
bin100101010111010101…
…101001111110011011
310211120000212012010011
4211113111221332123
51124131210003121
630233022502351
72620132243141
oct452725517633
9124500765104
1040120000411
1116018770137
1279381349b7
133a24ba971a
141d284c7591
15109c2dc7e1
hex957569f9b

40120000411 has 4 divisors (see below), whose sum is σ = 42231579400. Its totient is φ = 38008421424.

The previous prime is 40120000379. The next prime is 40120000447. The reversal of 40120000411 is 11400002104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40120000411 - 25 = 40120000379 is a prime.

It is a super-2 number, since 2×401200004112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40120000391 and 40120000400.

It is not an unprimeable number, because it can be changed into a prime (40120000511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1055789466 + ... + 1055789503.

It is an arithmetic number, because the mean of its divisors is an integer number (10557894850).

Almost surely, 240120000411 is an apocalyptic number.

40120000411 is a deficient number, since it is larger than the sum of its proper divisors (2111578989).

40120000411 is a wasteful number, since it uses less digits than its factorization.

40120000411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2111578988.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 40120000411 its reverse (11400002104), we get a palindrome (51520002515).

The spelling of 40120000411 in words is "forty billion, one hundred twenty million, four hundred eleven", and thus it is an aban number.

Divisors: 1 19 2111578969 40120000411