Base | Representation |
---|---|
bin | 111010011000011111001… |
… | …110010110110000001011 |
3 | 112012112201210200012110201 |
4 | 322120133032112300023 |
5 | 1011213110431430441 |
6 | 12311033103153031 |
7 | 562600451320045 |
oct | 72303716266013 |
9 | 15175653605421 |
10 | 4012023311371 |
11 | 1307542625439 |
12 | 5496825a5777 |
13 | 231441a3296a |
14 | dc27c0a8a95 |
15 | 6e5667d2c31 |
hex | 3a61f396c0b |
4012023311371 has 2 divisors, whose sum is σ = 4012023311372. Its totient is φ = 4012023311370.
The previous prime is 4012023311297. The next prime is 4012023311399. The reversal of 4012023311371 is 1731133202104.
It is an a-pointer prime, because the next prime (4012023311399) can be obtained adding 4012023311371 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4012023311371 - 213 = 4012023303179 is a prime.
It is not a weakly prime, because it can be changed into another prime (4012023311671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006011655685 + 2006011655686.
It is an arithmetic number, because the mean of its divisors is an integer number (2006011655686).
Almost surely, 24012023311371 is an apocalyptic number.
4012023311371 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012023311371 is an equidigital number, since it uses as much as digits as its factorization.
4012023311371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 4012023311371 its reverse (1731133202104), we get a palindrome (5743156513475).
The spelling of 4012023311371 in words is "four trillion, twelve billion, twenty-three million, three hundred eleven thousand, three hundred seventy-one".
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