Base | Representation |
---|---|
bin | 101101100111001000110110… |
… | …0001111011010100101100111 |
3 | 1221121112122211212110010221111 |
4 | 1123032101230033122211213 |
5 | 410041303330031044333 |
6 | 3541142130240125451 |
7 | 150335660544646243 |
oct | 13316215417324547 |
9 | 1847478755403844 |
10 | 401203301034343 |
11 | 1069214010a3745 |
12 | 38bb7a79906887 |
13 | 142b34029ba802 |
14 | 71104b433b423 |
15 | 315b342a234cd |
hex | 16ce46c3da967 |
401203301034343 has 2 divisors, whose sum is σ = 401203301034344. Its totient is φ = 401203301034342.
The previous prime is 401203301034329. The next prime is 401203301034353. The reversal of 401203301034343 is 343430103302104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 401203301034343 - 217 = 401203300903271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401203301034353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200601650517171 + 200601650517172.
It is an arithmetic number, because the mean of its divisors is an integer number (200601650517172).
Almost surely, 2401203301034343 is an apocalyptic number.
401203301034343 is a deficient number, since it is larger than the sum of its proper divisors (1).
401203301034343 is an equidigital number, since it uses as much as digits as its factorization.
401203301034343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 401203301034343 its reverse (343430103302104), we get a palindrome (744633404336447).
The spelling of 401203301034343 in words is "four hundred one trillion, two hundred three billion, three hundred one million, thirty-four thousand, three hundred forty-three".
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