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4012034113397 is a prime number
BaseRepresentation
bin111010011000011111110…
…111100011111101110101
3112012112202120000000001202
4322120133313203331311
51011213121213112042
612311034130502245
7562600642166612
oct72303767437565
915175676000052
104012034113397
111307548733132
12549686134985
132314440455ab
14dc27d6bb509
156e567718632
hex3a61fde3f75

4012034113397 has 2 divisors, whose sum is σ = 4012034113398. Its totient is φ = 4012034113396.

The previous prime is 4012034113393. The next prime is 4012034113481. The reversal of 4012034113397 is 7933114302104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3313415637841 + 698618475556 = 1820279^2 + 835834^2 .

It is a cyclic number.

It is not a de Polignac number, because 4012034113397 - 22 = 4012034113393 is a prime.

It is a super-2 number, since 2×40120341133972 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4012034113397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4012034113393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006017056698 + 2006017056699.

It is an arithmetic number, because the mean of its divisors is an integer number (2006017056699).

Almost surely, 24012034113397 is an apocalyptic number.

It is an amenable number.

4012034113397 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012034113397 is an equidigital number, since it uses as much as digits as its factorization.

4012034113397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 38.

The spelling of 4012034113397 in words is "four trillion, twelve billion, thirty-four million, one hundred thirteen thousand, three hundred ninety-seven".