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4012103131 is a prime number
BaseRepresentation
bin1110111100100011…
…1101010111011011
3101100121110221211021
43233020331113123
531204044300011
61502041143311
7201265212451
oct35710752733
911317427737
104012103131
111779800513
1293b78ab37
134bc29b62a
142a0bc49d1
15187366471
hexef23d5db

4012103131 has 2 divisors, whose sum is σ = 4012103132. Its totient is φ = 4012103130.

The previous prime is 4012103047. The next prime is 4012103149. The reversal of 4012103131 is 1313012104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4012103131 - 225 = 3978548699 is a prime.

It is a super-2 number, since 2×40121031312 = 32193943067560006322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4012103231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006051565 + 2006051566.

It is an arithmetic number, because the mean of its divisors is an integer number (2006051566).

Almost surely, 24012103131 is an apocalyptic number.

4012103131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4012103131 is an equidigital number, since it uses as much as digits as its factorization.

4012103131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 4012103131 is about 63341.1645851258. The cubic root of 4012103131 is about 1589.0004834473. Note that the first 3 decimals are identical.

Adding to 4012103131 its reverse (1313012104), we get a palindrome (5325115235).

The spelling of 4012103131 in words is "four billion, twelve million, one hundred three thousand, one hundred thirty-one".