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4012113202241 = 15312620583411
BaseRepresentation
bin111010011000100100100…
…101010000110001000001
3112012112222001211010120012
4322120210211100301001
51011213301434432431
612311050033554305
7562602622346414
oct72304445206101
915175861733505
104012113202241
111307589341811
125496a8715995
13231457547021
14dc289dc7b7b
156e56e63c22b
hex3a624950c41

4012113202241 has 4 divisors (see below), whose sum is σ = 4014733787184. Its totient is φ = 4009492617300.

The previous prime is 4012113202217. The next prime is 4012113202249. The reversal of 4012113202241 is 1422023112104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4012113202241 - 234 = 3994933333057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4012113202249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310290175 + ... + 1310293236.

It is an arithmetic number, because the mean of its divisors is an integer number (1003683446796).

Almost surely, 24012113202241 is an apocalyptic number.

It is an amenable number.

4012113202241 is a deficient number, since it is larger than the sum of its proper divisors (2620584943).

4012113202241 is a wasteful number, since it uses less digits than its factorization.

4012113202241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2620584942.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 4012113202241 its reverse (1422023112104), we get a palindrome (5434136314345).

The spelling of 4012113202241 in words is "four trillion, twelve billion, one hundred thirteen million, two hundred two thousand, two hundred forty-one".

Divisors: 1 1531 2620583411 4012113202241