Base | Representation |
---|---|
bin | 10010001111101100011100… |
… | …10011110101001010111101 |
3 | 12021001121001122210212101202 |
4 | 21013312032103311022331 |
5 | 20224323143312401013 |
6 | 221155351034145245 |
7 | 11310460363111013 |
oct | 1107661623651275 |
9 | 167047048725352 |
10 | 40121677075133 |
11 | 118695648145a5 |
12 | 45bba24582225 |
13 | 19505c5062884 |
14 | 9c9c8445a8b3 |
15 | 4989cc048858 |
hex | 247d8e4f52bd |
40121677075133 has 2 divisors, whose sum is σ = 40121677075134. Its totient is φ = 40121677075132.
The previous prime is 40121677075127. The next prime is 40121677075147. The reversal of 40121677075133 is 33157077612104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32738789255524 + 7382887819609 = 5721782^2 + 2717147^2 .
It is a cyclic number.
It is not a de Polignac number, because 40121677075133 - 28 = 40121677074877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40121677075033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20060838537566 + 20060838537567.
It is an arithmetic number, because the mean of its divisors is an integer number (20060838537567).
Almost surely, 240121677075133 is an apocalyptic number.
It is an amenable number.
40121677075133 is a deficient number, since it is larger than the sum of its proper divisors (1).
40121677075133 is an equidigital number, since it uses as much as digits as its factorization.
40121677075133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 740880, while the sum is 47.
The spelling of 40121677075133 in words is "forty trillion, one hundred twenty-one billion, six hundred seventy-seven million, seventy-five thousand, one hundred thirty-three".
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