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401220215523011 is a prime number
BaseRepresentation
bin101101100111010000101110…
…0011011000100011011000011
31221121121021111200001012100202
41123032201130123010123003
5410042043000133214021
63541154004504235415
7150340126652511263
oct13316413433043303
91847537450035322
10401220215523011
111069285a09673a5
1238bbb1ba46bb6b
13142b4b9a0710a1
14711123a91b7a3
15315b9d2958a0b
hex16ce85c6c46c3

401220215523011 has 2 divisors, whose sum is σ = 401220215523012. Its totient is φ = 401220215523010.

The previous prime is 401220215522999. The next prime is 401220215523013. The reversal of 401220215523011 is 110325512022104.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 401220215523011 - 230 = 401219141781187 is a prime.

It is a super-2 number, since 2×4012202155230112 (a number of 30 digits) contains 22 as substring.

Together with 401220215523013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (401220215523013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200610107761505 + 200610107761506.

It is an arithmetic number, because the mean of its divisors is an integer number (200610107761506).

Almost surely, 2401220215523011 is an apocalyptic number.

401220215523011 is a deficient number, since it is larger than the sum of its proper divisors (1).

401220215523011 is an equidigital number, since it uses as much as digits as its factorization.

401220215523011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 401220215523011 its reverse (110325512022104), we get a palindrome (511545727545115).

The spelling of 401220215523011 in words is "four hundred one trillion, two hundred twenty billion, two hundred fifteen million, five hundred twenty-three thousand, eleven".