Base | Representation |
---|---|
bin | 111010011000101010100… |
… | …110100101101101000011 |
3 | 112012120020002220000212211 |
4 | 322120222212211231003 |
5 | 1011214003314312233 |
6 | 12311104043002551 |
7 | 562605260052622 |
oct | 72305246455503 |
9 | 15176202800784 |
10 | 4012214213443 |
11 | 1307630363a47 |
12 | 549716509457 |
13 | 231472452b77 |
14 | dc29959d6b9 |
15 | 6e5784415cd |
hex | 3a62a9a5b43 |
4012214213443 has 2 divisors, whose sum is σ = 4012214213444. Its totient is φ = 4012214213442.
The previous prime is 4012214213411. The next prime is 4012214213507. The reversal of 4012214213443 is 3443124122104.
It is a happy number.
4012214213443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4012214213443 - 25 = 4012214213411 is a prime.
It is not a weakly prime, because it can be changed into another prime (4012214217443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006107106721 + 2006107106722.
It is an arithmetic number, because the mean of its divisors is an integer number (2006107106722).
Almost surely, 24012214213443 is an apocalyptic number.
4012214213443 is a deficient number, since it is larger than the sum of its proper divisors (1).
4012214213443 is an equidigital number, since it uses as much as digits as its factorization.
4012214213443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 4012214213443 its reverse (3443124122104), we get a palindrome (7455338335547).
The spelling of 4012214213443 in words is "four trillion, twelve billion, two hundred fourteen million, two hundred thirteen thousand, four hundred forty-three".
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