Search a number
-
+
4012301402013 = 31337433800671
BaseRepresentation
bin111010011000101111110…
…011001011111110011101
3112012120110011221200010010
4322120233303023332131
51011214143124331023
612311120435433433
7562610366125662
oct72305763137635
915176404850103
104012301402013
1113076755a5013
1254973b755879
1323148752c238
14dc2a6db7a69
156e580e15093
hex3a62fccbf9d

4012301402013 has 4 divisors (see below), whose sum is σ = 5349735202688. Its totient is φ = 2674867601340.

The previous prime is 4012301401991. The next prime is 4012301402017. The reversal of 4012301402013 is 3102041032104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 4012301402013 - 217 = 4012301270941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4012301402017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668716900333 + ... + 668716900338.

It is an arithmetic number, because the mean of its divisors is an integer number (1337433800672).

Almost surely, 24012301402013 is an apocalyptic number.

It is an amenable number.

4012301402013 is a deficient number, since it is larger than the sum of its proper divisors (1337433800675).

4012301402013 is a wasteful number, since it uses less digits than its factorization.

4012301402013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337433800674.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 4012301402013 its reverse (3102041032104), we get a palindrome (7114342434117).

The spelling of 4012301402013 in words is "four trillion, twelve billion, three hundred one million, four hundred two thousand, thirteen".

Divisors: 1 3 1337433800671 4012301402013