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40123150400000 = 2955231090303
BaseRepresentation
bin10010001111101111001100…
…01000000111101000000000
312021001201212100010112011102
421013313212020013220000
520224334203000300000
6221200153144433532
711310542033135543
oct1107674610075000
9167051770115142
1040123150400000
111186a150435358
124600175a788a8
13195079b375335
149c9d83db885a
15498a665743d5
hex247de6207a00

40123150400000 has 240 divisors, whose sum is σ = 104560275714048. Its totient is φ = 15351452160000.

The previous prime is 40123150399991. The next prime is 40123150400009. The reversal of 40123150400000 is 405132104.

It is an interprime number because it is at equal distance from previous prime (40123150399991) and next prime (40123150400009).

It is a super-3 number, since 3×401231504000003 (a number of 42 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (40123150400009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36254849 + ... + 37345151.

Almost surely, 240123150400000 is an apocalyptic number.

40123150400000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 40123150400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (52280137857024).

40123150400000 is an abundant number, since it is smaller than the sum of its proper divisors (64437125314048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

40123150400000 is an frugal number, since it uses more digits than its factorization.

40123150400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1090369 (or 1090333 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 20.

Adding to 40123150400000 its reverse (405132104), we get a palindrome (40123555532104).

The spelling of 40123150400000 in words is "forty trillion, one hundred twenty-three billion, one hundred fifty million, four hundred thousand".