Base | Representation |
---|---|
bin | 101101100111010111010000… |
… | …1010100000011110100010001 |
3 | 1221121122121202012002021021120 |
4 | 1123032232201110003310101 |
5 | 410042310224042342223 |
6 | 3541204250033112453 |
7 | 150341134623440253 |
oct | 13316564124036421 |
9 | 1847577665067246 |
10 | 401234256215313 |
11 | 106933546529334 |
12 | 39001a786b8729 |
13 | 142b62c6c29941 |
14 | 7111bad587cd3 |
15 | 315c055428be3 |
hex | 16ceba1503d11 |
401234256215313 has 16 divisors (see below), whose sum is σ = 566451685105920. Its totient is φ = 251753350366976.
The previous prime is 401234256215311. The next prime is 401234256215393. The reversal of 401234256215313 is 313512652432104.
It is a cyclic number.
It is not a de Polignac number, because 401234256215313 - 21 = 401234256215311 is a prime.
It is not an unprimeable number, because it can be changed into a prime (401234256215311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14268633 + ... + 31718486.
It is an arithmetic number, because the mean of its divisors is an integer number (35403230319120).
Almost surely, 2401234256215313 is an apocalyptic number.
It is an amenable number.
401234256215313 is a deficient number, since it is larger than the sum of its proper divisors (165217428890607).
401234256215313 is a wasteful number, since it uses less digits than its factorization.
401234256215313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46158216.
The product of its (nonzero) digits is 518400, while the sum is 42.
The spelling of 401234256215313 in words is "four hundred one trillion, two hundred thirty-four billion, two hundred fifty-six million, two hundred fifteen thousand, three hundred thirteen".
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