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401251130552807 is a prime number
BaseRepresentation
bin101101100111011111000111…
…1000110100011000111100111
31221121201020022012010102122022
41123032332033012203013213
5410043044303410142212
63541220120304453355
7150342303033104423
oct13316761706430747
91847636265112568
10401251130552807
1110693a7156688a7
12390051a791a25b
13142b7a85b92922
1471129306b5b83
15315c6e1a7c772
hex16cef8f1a31e7

401251130552807 has 2 divisors, whose sum is σ = 401251130552808. Its totient is φ = 401251130552806.

The previous prime is 401251130552803. The next prime is 401251130552819. The reversal of 401251130552807 is 708255031152104.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 401251130552807 - 22 = 401251130552803 is a prime.

It is a super-2 number, since 2×4012511305528072 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (401251130552803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200625565276403 + 200625565276404.

It is an arithmetic number, because the mean of its divisors is an integer number (200625565276404).

Almost surely, 2401251130552807 is an apocalyptic number.

401251130552807 is a deficient number, since it is larger than the sum of its proper divisors (1).

401251130552807 is an equidigital number, since it uses as much as digits as its factorization.

401251130552807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336000, while the sum is 44.

The spelling of 401251130552807 in words is "four hundred one trillion, two hundred fifty-one billion, one hundred thirty million, five hundred fifty-two thousand, eight hundred seven".