40125403 has 2 divisors, whose sum is σ = 40125404. Its totient is φ = 40125402.

The previous prime is 40125341. The next prime is 40125413. The reversal of 40125403 is 30452104.

40125403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40125403 - 2¹³ = 40117211 is a prime.

It is a super-2 number, since 2×40125403² = 3220095931824818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40125413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20062701 + 20062702.

It is an arithmetic number, because the mean of its divisors is an integer number (20062702).

Almost surely, 2^40125403 is an apocalyptic number.

40125403 is a deficient number, since it is larger than the sum of its proper divisors (1).

40125403 is an equidigital number, since it uses as much as digits as its factorization.

40125403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 19.

The square root of 40125403 is about 6334.4615398627. The cubic root of 40125403 is about 342.3522100221.

Adding to 40125403 its reverse (30452104), we get a palindrome (70577507).

The spelling of 40125403 in words is "forty million, one hundred twenty-five thousand, four hundred three".