Base | Representation |
---|---|
bin | 1011101011011110101… |
… | …10011100010000000111 |
3 | 1102100211021221220220121 |
4 | 11311233112130100013 |
5 | 23033330312044031 |
6 | 504204342042411 |
7 | 40664406450103 |
oct | 5655726342007 |
9 | 1370737856817 |
10 | 401300112391 |
11 | 1452104a7052 |
12 | 65936719407 |
13 | 2bac4ab5509 |
14 | 155ccb12903 |
15 | a68ab0c011 |
hex | 5d6f59c407 |
401300112391 has 2 divisors, whose sum is σ = 401300112392. Its totient is φ = 401300112390.
The previous prime is 401300112359. The next prime is 401300112449. The reversal of 401300112391 is 193211003104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 401300112391 - 25 = 401300112359 is a prime.
It is a super-2 number, since 2×4013001123912 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (401300112331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200650056195 + 200650056196.
It is an arithmetic number, because the mean of its divisors is an integer number (200650056196).
Almost surely, 2401300112391 is an apocalyptic number.
401300112391 is a deficient number, since it is larger than the sum of its proper divisors (1).
401300112391 is an equidigital number, since it uses as much as digits as its factorization.
401300112391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 401300112391 its reverse (193211003104), we get a palindrome (594511115495).
The spelling of 401300112391 in words is "four hundred one billion, three hundred million, one hundred twelve thousand, three hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •