Base | Representation |
---|---|
bin | 100101010111111011… |
… | …111101001001010011 |
3 | 10211120201202021101201 |
4 | 211113323331021103 |
5 | 1124141242243103 |
6 | 30234022012031 |
7 | 2620313500225 |
oct | 452773751123 |
9 | 124521667351 |
10 | 40130040403 |
11 | 160233a8352 |
12 | 793b577017 |
13 | 3a26cb354b |
14 | 1d2997c415 |
15 | 109d12251d |
hex | 957efd253 |
40130040403 has 2 divisors, whose sum is σ = 40130040404. Its totient is φ = 40130040402.
The previous prime is 40130040367. The next prime is 40130040437. The reversal of 40130040403 is 30404003104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40130040403 - 217 = 40129909331 is a prime.
It is a super-2 number, since 2×401300404032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40130041403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065020201 + 20065020202.
It is an arithmetic number, because the mean of its divisors is an integer number (20065020202).
Almost surely, 240130040403 is an apocalyptic number.
40130040403 is a deficient number, since it is larger than the sum of its proper divisors (1).
40130040403 is an equidigital number, since it uses as much as digits as its factorization.
40130040403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 19.
Adding to 40130040403 its reverse (30404003104), we get a palindrome (70534043507).
The spelling of 40130040403 in words is "forty billion, one hundred thirty million, forty thousand, four hundred three".
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