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40130040437 is a prime number
BaseRepresentation
bin100101010111111011…
…111101001001110101
310211120201202021102222
4211113323331021311
51124141242243222
630234022012125
72620313500304
oct452773751165
9124521667388
1040130040437
11160233a8383
12793b577045
133a26cb3576
141d2997c43b
15109d122542
hex957efd275

40130040437 has 2 divisors, whose sum is σ = 40130040438. Its totient is φ = 40130040436.

The previous prime is 40130040403. The next prime is 40130040439. The reversal of 40130040437 is 73404003104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33538061956 + 6591978481 = 183134^2 + 81191^2 .

It is a cyclic number.

It is not a de Polignac number, because 40130040437 - 210 = 40130039413 is a prime.

It is a super-2 number, since 2×401300404372 (a number of 22 digits) contains 22 as substring.

Together with 40130040439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40130040439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065020218 + 20065020219.

It is an arithmetic number, because the mean of its divisors is an integer number (20065020219).

Almost surely, 240130040437 is an apocalyptic number.

It is an amenable number.

40130040437 is a deficient number, since it is larger than the sum of its proper divisors (1).

40130040437 is an equidigital number, since it uses as much as digits as its factorization.

40130040437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 26.

The spelling of 40130040437 in words is "forty billion, one hundred thirty million, forty thousand, four hundred thirty-seven".