Base | Representation |
---|---|
bin | 10010001111111100001001… |
… | …00011011000100000001011 |
3 | 12021002101210220021011201011 |
4 | 21013332010203120200023 |
5 | 20224442422422030233 |
6 | 221203303121504351 |
7 | 11311206241006252 |
oct | 1107760443304013 |
9 | 167071726234634 |
10 | 40130103314443 |
11 | 1187209914993a |
12 | 46015964a20b7 |
13 | 19513389a35ac |
14 | 9ca443599799 |
15 | 498d21b8c0cd |
hex | 247f848d880b |
40130103314443 has 2 divisors, whose sum is σ = 40130103314444. Its totient is φ = 40130103314442.
The previous prime is 40130103314423. The next prime is 40130103314447. The reversal of 40130103314443 is 34441330103104.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40130103314443 - 217 = 40130103183371 is a prime.
It is a super-2 number, since 2×401301033144432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40130103314447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065051657221 + 20065051657222.
It is an arithmetic number, because the mean of its divisors is an integer number (20065051657222).
Almost surely, 240130103314443 is an apocalyptic number.
40130103314443 is a deficient number, since it is larger than the sum of its proper divisors (1).
40130103314443 is an equidigital number, since it uses as much as digits as its factorization.
40130103314443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 40130103314443 its reverse (34441330103104), we get a palindrome (74571433417547).
The spelling of 40130103314443 in words is "forty trillion, one hundred thirty billion, one hundred three million, three hundred fourteen thousand, four hundred forty-three".
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