40131307655581 has 2 divisors, whose sum is σ = 40131307655582. Its totient is φ = 40131307655580.

The previous prime is 40131307655497. The next prime is 40131307655633. The reversal of 40131307655581 is 18555670313104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31981230488025 + 8150077167556 = 5655195^2 + 2854834^2 .

It is a cyclic number.

It is not a de Polignac number, because 40131307655581 - 2³⁹ = 39581551841693 is a prime.

It is a super-2 number, since 2×40131307655581² (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40131307652581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065653827790 + 20065653827791.

It is an arithmetic number, because the mean of its divisors is an integer number (20065653827791).

Almost surely, 2^{40131307655581} is an apocalyptic number.

It is an amenable number.

40131307655581 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131307655581 is an equidigital number, since it uses as much as digits as its factorization.

40131307655581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512000, while the sum is 49.

Adding to 40131307655581 its reverse (18555670313104), we get a palindrome (58686977968685).

The spelling of 40131307655581 in words is "forty trillion, one hundred thirty-one billion, three hundred seven million, six hundred fifty-five thousand, five hundred eighty-one".