4013131101207 has 4 divisors (see below), whose sum is σ = 5350841468280. Its totient is φ = 2675420734136.

The previous prime is 4013131101193. The next prime is 4013131101227. The reversal of 4013131101207 is 7021011313104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4013131101207 - 2¹⁵ = 4013131068439 is a prime.

It is a super-2 number, since 2×4013131101207² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013131101227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668855183532 + ... + 668855183537.

It is an arithmetic number, because the mean of its divisors is an integer number (1337710367070).

Almost surely, 2^{4013131101207} is an apocalyptic number.

4013131101207 is a deficient number, since it is larger than the sum of its proper divisors (1337710367073).

4013131101207 is a wasteful number, since it uses less digits than its factorization.

4013131101207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1337710367072.

The product of its (nonzero) digits is 504, while the sum is 24.

The spelling of 4013131101207 in words is "four trillion, thirteen billion, one hundred thirty-one million, one hundred one thousand, two hundred seven".