4013151241101 has 4 divisors (see below), whose sum is σ = 5350868321472. Its totient is φ = 2675434160732.

The previous prime is 4013151241091. The next prime is 4013151241123. The reversal of 4013151241101 is 1011421513104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4013151241101 - 2⁵ = 4013151241069 is a prime.

It is a super-2 number, since 2×4013151241101² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013151241301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 668858540181 + ... + 668858540186.

It is an arithmetic number, because the mean of its divisors is an integer number (1337717080368).

Almost surely, 2^{4013151241101} is an apocalyptic number.

It is an amenable number.

4013151241101 is a deficient number, since it is larger than the sum of its proper divisors (1337717080371).

4013151241101 is a wasteful number, since it uses less digits than its factorization.

4013151241101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1337717080370.

The product of its (nonzero) digits is 480, while the sum is 24.

Adding to 4013151241101 its reverse (1011421513104), we get a palindrome (5024572754205).

The spelling of 4013151241101 in words is "four trillion, thirteen billion, one hundred fifty-one million, two hundred forty-one thousand, one hundred one".