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40131554828077 is a prime number
BaseRepresentation
bin10010001111111110110110…
…00100011101111100101101
312021002112120001112201002101
421013333123010131330231
520230003411013444302
6221204103132455101
711311260224452366
oct1107773304357455
9167075501481071
1040131554828077
1111872773522589
12460192061a491
13195150a61a3bb
149ca54027ab6d
15498da930a287
hex247fdb11df2d

40131554828077 has 2 divisors, whose sum is σ = 40131554828078. Its totient is φ = 40131554828076.

The previous prime is 40131554828063. The next prime is 40131554828089. The reversal of 40131554828077 is 77082845513104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38292965273161 + 1838589554916 = 6188131^2 + 1355946^2 .

It is a cyclic number.

It is not a de Polignac number, because 40131554828077 - 211 = 40131554826029 is a prime.

It is a super-2 number, since 2×401315548280772 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40131554828377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065777414038 + 20065777414039.

It is an arithmetic number, because the mean of its divisors is an integer number (20065777414039).

Almost surely, 240131554828077 is an apocalyptic number.

It is an amenable number.

40131554828077 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131554828077 is an equidigital number, since it uses as much as digits as its factorization.

40131554828077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7526400, while the sum is 55.

The spelling of 40131554828077 in words is "forty trillion, one hundred thirty-one billion, five hundred fifty-four million, eight hundred twenty-eight thousand, seventy-seven".