Base | Representation |
---|---|
bin | 10010001111111111001101… |
… | …11111011000110101011011 |
3 | 12021002120001222212111112212 |
4 | 21013333212333120311123 |
5 | 20230004313213314003 |
6 | 221204135035225335 |
7 | 11311265203416104 |
oct | 1107774677306533 |
9 | 167076058774485 |
10 | 40131754823003 |
11 | 11872866401748 |
12 | 46019775a824b |
13 | 195153cba22ac |
14 | 9ca55ca5b3ab |
15 | 498dbbb62dd8 |
hex | 247fe6fd8d5b |
40131754823003 has 2 divisors, whose sum is σ = 40131754823004. Its totient is φ = 40131754823002.
The previous prime is 40131754822993. The next prime is 40131754823011. The reversal of 40131754823003 is 30032845713104.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40131754823003 - 240 = 39032243195227 is a prime.
It is a super-2 number, since 2×401317548230032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40131754823063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065877411501 + 20065877411502.
It is an arithmetic number, because the mean of its divisors is an integer number (20065877411502).
Almost surely, 240131754823003 is an apocalyptic number.
40131754823003 is a deficient number, since it is larger than the sum of its proper divisors (1).
40131754823003 is an equidigital number, since it uses as much as digits as its factorization.
40131754823003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 41.
The spelling of 40131754823003 in words is "forty trillion, one hundred thirty-one billion, seven hundred fifty-four million, eight hundred twenty-three thousand, three".
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