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40132063454797 is a prime number
BaseRepresentation
bin10010001111111111110010…
…11000101110011001001101
312021002120212111121121210001
421013333321120232121031
520230010431221023142
6221204225422244301
711311305641636206
oct1107777130563115
9167076774547701
1040132063454797
1111872a04641346
124601a42a26691
13195158bb02c62
149ca58ba3a5ad
15498dd8cc95b7
hex247ff962e64d

40132063454797 has 2 divisors, whose sum is σ = 40132063454798. Its totient is φ = 40132063454796.

The previous prime is 40132063454731. The next prime is 40132063454809. The reversal of 40132063454797 is 79745436023104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33113453116041 + 7018610338756 = 5754429^2 + 2649266^2 .

It is a cyclic number.

It is not a de Polignac number, because 40132063454797 - 211 = 40132063452749 is a prime.

It is a super-2 number, since 2×401320634547972 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40132063454297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066031727398 + 20066031727399.

It is an arithmetic number, because the mean of its divisors is an integer number (20066031727399).

Almost surely, 240132063454797 is an apocalyptic number.

It is an amenable number.

40132063454797 is a deficient number, since it is larger than the sum of its proper divisors (1).

40132063454797 is an equidigital number, since it uses as much as digits as its factorization.

40132063454797 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15240960, while the sum is 55.

The spelling of 40132063454797 in words is "forty trillion, one hundred thirty-two billion, sixty-three million, four hundred fifty-four thousand, seven hundred ninety-seven".