4013220143 has 4 divisors (see below), whose sum is σ = 4106550888. Its totient is φ = 3919889400.

The previous prime is 4013220137. The next prime is 4013220149. The reversal of 4013220143 is 3410223104.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (4013220137) and next prime (4013220149).

It is a cyclic number.

It is not a de Polignac number, because 4013220143 - 2¹⁴ = 4013203759 is a prime.

It is a super-2 number, since 2×4013220143² = 32211871832361880898, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013220149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46665308 + ... + 46665393.

It is an arithmetic number, because the mean of its divisors is an integer number (1026637722).

Almost surely, 2^4013220143 is an apocalyptic number.

4013220143 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

4013220143 is a deficient number, since it is larger than the sum of its proper divisors (93330745).

4013220143 is an equidigital number, since it uses as much as digits as its factorization.

4013220143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93330744.

The product of its (nonzero) digits is 576, while the sum is 20.

The square root of 4013220143 is about 63349.9813969981. The cubic root of 4013220143 is about 1589.1479346182.

Adding to 4013220143 its reverse (3410223104), we get a palindrome (7423443247).

The spelling of 4013220143 in words is "four billion, thirteen million, two hundred twenty thousand, one hundred forty-three".