Base | Representation |
---|---|
bin | 111010011001100110100… |
… | …111110101101110000011 |
3 | 112012122211021122221021201 |
4 | 322121212213311232003 |
5 | 1011223034110033042 |
6 | 12311352013402031 |
7 | 562642235064253 |
oct | 72314647655603 |
9 | 15178737587251 |
10 | 4013221174147 |
11 | 1307aa7801479 |
12 | 549957799317 |
13 | 2315a2c593c3 |
14 | dc3531dd963 |
15 | 6e5d6a4a1b7 |
hex | 3a6669f5b83 |
4013221174147 has 2 divisors, whose sum is σ = 4013221174148. Its totient is φ = 4013221174146.
The previous prime is 4013221174099. The next prime is 4013221174223. The reversal of 4013221174147 is 7414711223104.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4013221174147 - 215 = 4013221141379 is a prime.
It is a super-2 number, since 2×40132211741472 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4013221174847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006610587073 + 2006610587074.
It is an arithmetic number, because the mean of its divisors is an integer number (2006610587074).
Almost surely, 24013221174147 is an apocalyptic number.
4013221174147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013221174147 is an equidigital number, since it uses as much as digits as its factorization.
4013221174147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37632, while the sum is 37.
The spelling of 4013221174147 in words is "four trillion, thirteen billion, two hundred twenty-one million, one hundred seventy-four thousand, one hundred forty-seven".
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