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4013303422001 is a prime number
BaseRepresentation
bin111010011001101011100…
…001100101110000110001
3112012200001000102120010112
4322121223201211300301
51011223221134001001
612311404112311105
7562644254142026
oct72315341456061
915180030376115
104013303422001
11130803a178505
1254997b242495
132315b6cc5983
14dc3600cd54d
156e5ddd94cbb
hex3a66b865c31

4013303422001 has 2 divisors, whose sum is σ = 4013303422002. Its totient is φ = 4013303422000.

The previous prime is 4013303421947. The next prime is 4013303422039. The reversal of 4013303422001 is 1002243033104.

4013303422001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2307664810000 + 1705638612001 = 1519100^2 + 1306001^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013303422001 - 26 = 4013303421937 is a prime.

It is a super-2 number, since 2×40133034220012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013303422301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006651711000 + 2006651711001.

It is an arithmetic number, because the mean of its divisors is an integer number (2006651711001).

Almost surely, 24013303422001 is an apocalyptic number.

It is an amenable number.

4013303422001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013303422001 is an equidigital number, since it uses as much as digits as its factorization.

4013303422001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 4013303422001 its reverse (1002243033104), we get a palindrome (5015546455105).

The spelling of 4013303422001 in words is "four trillion, thirteen billion, three hundred three million, four hundred twenty-two thousand, one".