4013310401 has 4 divisors (see below), whose sum is σ = 4098700032. Its totient is φ = 3927920772.

The previous prime is 4013310347. The next prime is 4013310409. The reversal of 4013310401 is 1040133104.

4013310401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4013310401 - 2⁶ = 4013310337 is a prime.

It is a super-2 number, since 2×4013310401² = 32213320749549561602, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4013310401.

It is not an unprimeable number, because it can be changed into a prime (4013310409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42694745 + ... + 42694838.

It is an arithmetic number, because the mean of its divisors is an integer number (1024675008).

Almost surely, 2^4013310401 is an apocalyptic number.

It is an amenable number.

4013310401 is a deficient number, since it is larger than the sum of its proper divisors (85389631).

4013310401 is an equidigital number, since it uses as much as digits as its factorization.

4013310401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85389630.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 4013310401 is about 63350.6937688925. The cubic root of 4013310401 is about 1589.1598479309.

Adding to 4013310401 its reverse (1040133104), we get a palindrome (5053443505).

The spelling of 4013310401 in words is "four billion, thirteen million, three hundred ten thousand, four hundred one".