Base | Representation |
---|---|
bin | 100101011000000111… |
… | …110010001100111111 |
3 | 10211120221120211001011 |
4 | 211120013302030333 |
5 | 1124143041010221 |
6 | 30234212300051 |
7 | 2620352033614 |
oct | 453007621477 |
9 | 124527524034 |
10 | 40133141311 |
11 | 1602512608a |
12 | 7940611627 |
13 | 3a2782aac3 |
14 | 1d2a14850b |
15 | 109d5361e1 |
hex | 9581f233f |
40133141311 has 2 divisors, whose sum is σ = 40133141312. Its totient is φ = 40133141310.
The previous prime is 40133141287. The next prime is 40133141329. The reversal of 40133141311 is 11314133104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40133141311 is a prime.
It is a super-2 number, since 2×401331413112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40133141371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066570655 + 20066570656.
It is an arithmetic number, because the mean of its divisors is an integer number (20066570656).
Almost surely, 240133141311 is an apocalyptic number.
40133141311 is a deficient number, since it is larger than the sum of its proper divisors (1).
40133141311 is an equidigital number, since it uses as much as digits as its factorization.
40133141311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 40133141311 its reverse (11314133104), we get a palindrome (51447274415).
The spelling of 40133141311 in words is "forty billion, one hundred thirty-three million, one hundred forty-one thousand, three hundred eleven".
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