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40133498529557 is a prime number
BaseRepresentation
bin10010010000000010011101…
…11011000110011100010101
312021002201120111221222021002
421020001032323012130111
520230021401110421212
6221205024045033045
711311356335604506
oct1110011673063425
9167081514858232
1040133498529557
1111873580707244
124602183555785
13195175a212514
149ca68647cbad
15498e6ec9bac2
hex24804eec6715

40133498529557 has 2 divisors, whose sum is σ = 40133498529558. Its totient is φ = 40133498529556.

The previous prime is 40133498529521. The next prime is 40133498529623. The reversal of 40133498529557 is 75592589433104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36049384924996 + 4084113604561 = 6004114^2 + 2020919^2 .

It is a cyclic number.

It is not a de Polignac number, because 40133498529557 - 210 = 40133498528533 is a prime.

It is a super-2 number, since 2×401334985295572 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40133498529493 and 40133498529502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40133498523557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066749264778 + 20066749264779.

It is an arithmetic number, because the mean of its divisors is an integer number (20066749264779).

Almost surely, 240133498529557 is an apocalyptic number.

It is an amenable number.

40133498529557 is a deficient number, since it is larger than the sum of its proper divisors (1).

40133498529557 is an equidigital number, since it uses as much as digits as its factorization.

40133498529557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 163296000, while the sum is 65.

The spelling of 40133498529557 in words is "forty trillion, one hundred thirty-three billion, four hundred ninety-eight million, five hundred twenty-nine thousand, five hundred fifty-seven".