Base | Representation |
---|---|
bin | 111010011001110001111… |
… | …100001011011001101101 |
3 | 112012200022111221220010210 |
4 | 322121301330023121231 |
5 | 1011223431212231323 |
6 | 12311422515253033 |
7 | 562650032045340 |
oct | 72316174133155 |
9 | 15180274856123 |
10 | 4013411055213 |
11 | 1308094a0297a |
12 | 5499ab2aa179 |
13 | 2316033ac971 |
14 | dc37050a457 |
15 | 6e5e8556293 |
hex | 3a671f0b66d |
4013411055213 has 32 divisors (see below), whose sum is σ = 6255539527680. Its totient is φ = 2241080432640.
The previous prime is 4013411055163. The next prime is 4013411055239. The reversal of 4013411055213 is 3125501143104.
It is not a de Polignac number, because 4013411055213 - 210 = 4013411054189 is a prime.
It is a super-3 number, since 3×40134110552133 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4013411055293) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2539153 + ... + 3804486.
It is an arithmetic number, because the mean of its divisors is an integer number (195485610240).
Almost surely, 24013411055213 is an apocalyptic number.
It is an amenable number.
4013411055213 is a deficient number, since it is larger than the sum of its proper divisors (2242128472467).
4013411055213 is a wasteful number, since it uses less digits than its factorization.
4013411055213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6344337.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 4013411055213 its reverse (3125501143104), we get a palindrome (7138912198317).
The spelling of 4013411055213 in words is "four trillion, thirteen billion, four hundred eleven million, fifty-five thousand, two hundred thirteen".
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