40134121 has 8 divisors (see below), whose sum is σ = 41328000. Its totient is φ = 38950560.

The previous prime is 40134113. The next prime is 40134169. The reversal of 40134121 is 12143104.

40134121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 40134121 - 2³ = 40134113 is a prime.

It is a super-2 number, since 2×40134121² = 3221495336885282, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40134095 and 40134104.

It is not an unprimeable number, because it can be changed into a prime (40134221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5700 + ... + 10618.

It is an arithmetic number, because the mean of its divisors is an integer number (5166000).

Almost surely, 2^40134121 is an apocalyptic number.

40134121 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

It is an amenable number.

40134121 is a deficient number, since it is larger than the sum of its proper divisors (1193879).

40134121 is a wasteful number, since it uses less digits than its factorization.

40134121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5159.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 40134121 is about 6335.1496430629. The cubic root of 40134121 is about 342.3770023831.

Adding to 40134121 its reverse (12143104), we get a palindrome (52277225).

The spelling of 40134121 in words is "forty million, one hundred thirty-four thousand, one hundred twenty-one".