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401344311341 = 23653165716127
BaseRepresentation
bin1011101011100011111…
…11000011000000101101
31102100221101010110110202
411311301333003000231
523033423120430331
6504213001243245
740665454234031
oct5656177030055
91370841113422
10401344311341
11145233445406
1265949493525
132bb00cbc33c
14155d493a1c1
15a68e93cecb
hex5d71fc302d

401344311341 has 16 divisors (see below), whose sum is σ = 419714555904. Its totient is φ = 383051585664.

The previous prime is 401344311331. The next prime is 401344311343. The reversal of 401344311341 is 143113443104.

It is not a de Polignac number, because 401344311341 - 210 = 401344310317 is a prime.

It is a super-2 number, since 2×4013443113412 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401344311343) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24878420 + ... + 24894546.

It is an arithmetic number, because the mean of its divisors is an integer number (26232159744).

Almost surely, 2401344311341 is an apocalyptic number.

It is an amenable number.

401344311341 is a deficient number, since it is larger than the sum of its proper divisors (18370244563).

401344311341 is a wasteful number, since it uses less digits than its factorization.

401344311341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18460.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 401344311341 its reverse (143113443104), we get a palindrome (544457754445).

The spelling of 401344311341 in words is "four hundred one billion, three hundred forty-four million, three hundred eleven thousand, three hundred forty-one".

Divisors: 1 23 653 1657 15019 16127 38111 370921 1082021 10530931 24886483 26722439 242211413 614616097 17449752667 401344311341