40134831773663 has 32 divisors (see below), whose sum is σ = 45997286952960. Its totient is φ = 34693160992000.

The previous prime is 40134831773567. The next prime is 40134831773753. The reversal of 40134831773663 is 36637713843104.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40134831773663 is a prime.

It is a super-2 number, since 2×40134831773663² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40134831773599 and 40134831773608.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40134831073663) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1104953 + ... + 9027213.

It is an arithmetic number, because the mean of its divisors is an integer number (1437415217280).

Almost surely, 2^{40134831773663} is an apocalyptic number.

40134831773663 is a deficient number, since it is larger than the sum of its proper divisors (5862455179297).

40134831773663 is a wasteful number, since it uses less digits than its factorization.

40134831773663 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7922599.

The product of its (nonzero) digits is 18289152, while the sum is 56.

The spelling of 40134831773663 in words is "forty trillion, one hundred thirty-four billion, eight hundred thirty-one million, seven hundred seventy-three thousand, six hundred sixty-three".