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401412111 = 3133804037
BaseRepresentation
bin10111111011010…
…001000000001111
31000222022211220020
4113323101000033
51310230141421
6103455353223
712642642462
oct2773210017
91028284806
10401412111
1119664a951
12b2522813
1365217279
143b4512d9
1525391dc6
hex17ed100f

401412111 has 4 divisors (see below), whose sum is σ = 535216152. Its totient is φ = 267608072.

The previous prime is 401412083. The next prime is 401412127. The reversal of 401412111 is 111214104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 401412111 - 25 = 401412079 is a prime.

It is a super-2 number, since 2×4014121112 = 322263365714952642, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401412131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66902016 + ... + 66902021.

It is an arithmetic number, because the mean of its divisors is an integer number (133804038).

Almost surely, 2401412111 is an apocalyptic number.

401412111 is a deficient number, since it is larger than the sum of its proper divisors (133804041).

401412111 is a wasteful number, since it uses less digits than its factorization.

401412111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 133804040.

The product of its (nonzero) digits is 32, while the sum is 15.

The square root of 401412111 is about 20035.2716727276. The cubic root of 401412111 is about 737.6723249903.

Adding to 401412111 its reverse (111214104), we get a palindrome (512626215).

The spelling of 401412111 in words is "four hundred one million, four hundred twelve thousand, one hundred eleven".

Divisors: 1 3 133804037 401412111