4014123144133 has 4 divisors (see below), whose sum is σ = 4014136059948. Its totient is φ = 4014110228320.

The previous prime is 4014123144121. The next prime is 4014123144149. The reversal of 4014123144133 is 3314413214104.

4014123144133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2630257945249 + 1383865198884 = 1621807^2 + 1176378^2 .

It is a cyclic number.

It is not a de Polignac number, because 4014123144133 - 2⁹ = 4014123143621 is a prime.

It is a super-2 number, since 2×4014123144133² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4014123144095 and 4014123144104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4014123144113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5979928 + ... + 6617233.

It is an arithmetic number, because the mean of its divisors is an integer number (1003534014987).

Almost surely, 2^{4014123144133} is an apocalyptic number.

It is an amenable number.

4014123144133 is a deficient number, since it is larger than the sum of its proper divisors (12915815).

4014123144133 is a wasteful number, since it uses less digits than its factorization.

4014123144133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12915814.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 4014123144133 its reverse (3314413214104), we get a palindrome (7328536358237).

The spelling of 4014123144133 in words is "four trillion, fourteen billion, one hundred twenty-three million, one hundred forty-four thousand, one hundred thirty-three".