401413244012333 has 8 divisors (see below), whose sum is σ = 459596673221952. Its totient is φ = 343439484818976.

The previous prime is 401413244012329. The next prime is 401413244012353. The reversal of 401413244012333 is 333210442314104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 401413244012333 - 2² = 401413244012329 is a prime.

It is a super-2 number, since 2×401413244012333² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401413244012293 and 401413244012302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401413244012353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52417499960 + ... + 52417507617.

It is an arithmetic number, because the mean of its divisors is an integer number (57449584152744).

Almost surely, 2^{401413244012333} is an apocalyptic number.

It is an amenable number.

401413244012333 is a deficient number, since it is larger than the sum of its proper divisors (58183429209619).

401413244012333 is a wasteful number, since it uses less digits than its factorization.

401413244012333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104835008131.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 401413244012333 its reverse (333210442314104), we get a palindrome (734623686326437).

The spelling of 401413244012333 in words is "four hundred one trillion, four hundred thirteen billion, two hundred forty-four million, twelve thousand, three hundred thirty-three".