Base | Representation |
---|---|
bin | 111010011010101111011… |
… | …110000010100010110011 |
3 | 112012202222110101111101212 |
4 | 322122233132002202303 |
5 | 1011233034443421003 |
6 | 12312113152550335 |
7 | 563014435250663 |
oct | 72325736024263 |
9 | 15182873344355 |
10 | 4014443342003 |
11 | 1308574679256 |
12 | 54a038b523ab |
13 | 231739212953 |
14 | dc42b6601a3 |
15 | 6e658eb3dd8 |
hex | 3a6af7828b3 |
4014443342003 has 2 divisors, whose sum is σ = 4014443342004. Its totient is φ = 4014443342002.
The previous prime is 4014443341981. The next prime is 4014443342009. The reversal of 4014443342003 is 3002433444104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4014443342003 - 214 = 4014443325619 is a prime.
It is a super-2 number, since 2×40144433420032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4014443342009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007221671001 + 2007221671002.
It is an arithmetic number, because the mean of its divisors is an integer number (2007221671002).
Almost surely, 24014443342003 is an apocalyptic number.
4014443342003 is a deficient number, since it is larger than the sum of its proper divisors (1).
4014443342003 is an equidigital number, since it uses as much as digits as its factorization.
4014443342003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 32.
Adding to 4014443342003 its reverse (3002433444104), we get a palindrome (7016876786107).
The spelling of 4014443342003 in words is "four trillion, fourteen billion, four hundred forty-three million, three hundred forty-two thousand, three".
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