Base | Representation |
---|---|
bin | 100101011000110101… |
… | …001011011011110101 |
3 | 10211121202222101112121 |
4 | 211120311023123311 |
5 | 1124204112304031 |
6 | 30235315315541 |
7 | 2620555135162 |
oct | 453065133365 |
9 | 124552871477 |
10 | 40145041141 |
11 | 16030913657 |
12 | 79445abbb1 |
13 | 3a2a13631a |
14 | 1d2b965069 |
15 | 109e5d7011 |
hex | 958d4b6f5 |
40145041141 has 2 divisors, whose sum is σ = 40145041142. Its totient is φ = 40145041140.
The previous prime is 40145041129. The next prime is 40145041159. The reversal of 40145041141 is 14114054104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40098460516 + 46580625 = 200246^2 + 6825^2 .
It is a cyclic number.
It is not a de Polignac number, because 40145041141 - 29 = 40145040629 is a prime.
It is a super-2 number, since 2×401450411412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40145041121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20072520570 + 20072520571.
It is an arithmetic number, because the mean of its divisors is an integer number (20072520571).
Almost surely, 240145041141 is an apocalyptic number.
It is an amenable number.
40145041141 is a deficient number, since it is larger than the sum of its proper divisors (1).
40145041141 is an equidigital number, since it uses as much as digits as its factorization.
40145041141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 40145041141 its reverse (14114054104), we get a palindrome (54259095245).
The spelling of 40145041141 in words is "forty billion, one hundred forty-five million, forty-one thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •