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40145254141 is a prime number
BaseRepresentation
bin100101011000110101…
…111111011011111101
310211121210101012201111
4211120311333123331
51124204141113031
630235324042021
72620560013156
oct453065773375
9124553335644
1040145254141
1116030a49693
127944693311
133a2a1ac265
141d2b9bc92d
15109e62a1b1
hex958d7f6fd

40145254141 has 2 divisors, whose sum is σ = 40145254142. Its totient is φ = 40145254140.

The previous prime is 40145254073. The next prime is 40145254157. The reversal of 40145254141 is 14145254104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38483061241 + 1662192900 = 196171^2 + 40770^2 .

It is a cyclic number.

It is not a de Polignac number, because 40145254141 - 27 = 40145254013 is a prime.

It is a super-2 number, since 2×401452541412 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40145252141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20072627070 + 20072627071.

It is an arithmetic number, because the mean of its divisors is an integer number (20072627071).

Almost surely, 240145254141 is an apocalyptic number.

It is an amenable number.

40145254141 is a deficient number, since it is larger than the sum of its proper divisors (1).

40145254141 is an equidigital number, since it uses as much as digits as its factorization.

40145254141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12800, while the sum is 31.

The spelling of 40145254141 in words is "forty billion, one hundred forty-five million, two hundred fifty-four thousand, one hundred forty-one".