40145354335553 has 4 divisors (see below), whose sum is σ = 40695290696388. Its totient is φ = 39595417974720.

The previous prime is 40145354335507. The next prime is 40145354335571. The reversal of 40145354335553 is 35553345354104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 21864667385089 + 18280686950464 = 4675967^2 + 4275592^2 .

It is a cyclic number.

It is not a de Polignac number, because 40145354335553 - 2³⁶ = 40076634858817 is a prime.

It is a super-2 number, since 2×40145354335553² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (40145354338553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 274968180308 + ... + 274968180453.

It is an arithmetic number, because the mean of its divisors is an integer number (10173822674097).

Almost surely, 2^{40145354335553} is an apocalyptic number.

It is an amenable number.

40145354335553 is a deficient number, since it is larger than the sum of its proper divisors (549936360835).

40145354335553 is an equidigital number, since it uses as much as digits as its factorization.

40145354335553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 549936360834.

The product of its (nonzero) digits is 16200000, while the sum is 50.

Adding to 40145354335553 its reverse (35553345354104), we get a palindrome (75698699689657).

The spelling of 40145354335553 in words is "forty trillion, one hundred forty-five billion, three hundred fifty-four million, three hundred thirty-five thousand, five hundred fifty-three".