Base | Representation |
---|---|
bin | 10010010000011000101010… |
… | …00111110011100010110111 |
3 | 12021010212022220102111112122 |
4 | 21020030111013303202313 |
5 | 20230220301400332013 |
6 | 221214314244110155 |
7 | 11312260530002351 |
oct | 1110142507634267 |
9 | 167125286374478 |
10 | 40145413683383 |
11 | 11878635487708 |
12 | 460454999535b |
13 | 195290890abb8 |
14 | 9cb096ad20d1 |
15 | 49941ad5ca08 |
hex | 2483151f38b7 |
40145413683383 has 2 divisors, whose sum is σ = 40145413683384. Its totient is φ = 40145413683382.
The previous prime is 40145413683337. The next prime is 40145413683409. The reversal of 40145413683383 is 38338631454104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40145413683383 - 214 = 40145413666999 is a prime.
It is a super-2 number, since 2×401454136833832 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40148413683383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20072706841691 + 20072706841692.
It is an arithmetic number, because the mean of its divisors is an integer number (20072706841692).
Almost surely, 240145413683383 is an apocalyptic number.
40145413683383 is a deficient number, since it is larger than the sum of its proper divisors (1).
40145413683383 is an equidigital number, since it uses as much as digits as its factorization.
40145413683383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9953280, while the sum is 53.
The spelling of 40145413683383 in words is "forty trillion, one hundred forty-five billion, four hundred thirteen million, six hundred eighty-three thousand, three hundred eighty-three".
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