Base | Representation |
---|---|
bin | 10010010000011001110110… |
… | …01100101000100111111111 |
3 | 12021010220222102102220200022 |
4 | 21020030323030220213333 |
5 | 20230223103413433313 |
6 | 221214501503522355 |
7 | 11312312414501534 |
oct | 1110147314504777 |
9 | 167126872386608 |
10 | 40146052483583 |
11 | 11878933026762 |
12 | 46046a78b93bb |
13 | 19529ab070197 |
14 | 9cb117898d8b |
15 | 499456e91c08 |
hex | 24833b3289ff |
40146052483583 has 2 divisors, whose sum is σ = 40146052483584. Its totient is φ = 40146052483582.
The previous prime is 40146052483577. The next prime is 40146052483627. The reversal of 40146052483583 is 38538425064104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40146052483583 - 212 = 40146052479487 is a prime.
It is a super-2 number, since 2×401460524835832 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40146052483553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20073026241791 + 20073026241792.
It is an arithmetic number, because the mean of its divisors is an integer number (20073026241792).
Almost surely, 240146052483583 is an apocalyptic number.
40146052483583 is a deficient number, since it is larger than the sum of its proper divisors (1).
40146052483583 is an equidigital number, since it uses as much as digits as its factorization.
40146052483583 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11059200, while the sum is 53.
The spelling of 40146052483583 in words is "forty trillion, one hundred forty-six billion, fifty-two million, four hundred eighty-three thousand, five hundred eighty-three".
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