Base | Representation |
---|---|
bin | 1011101011111000001… |
… | …00100111001011001001 |
3 | 1102101101011120021202201 |
4 | 11311330010213023021 |
5 | 23034244431323340 |
6 | 504241444400201 |
7 | 41002610540626 |
oct | 5657404471311 |
9 | 1371334507681 |
10 | 401513542345 |
11 | 14530aa22143 |
12 | 659960a6061 |
13 | 2bb2a092626 |
14 | 1560d1cd34d |
15 | a69e71a79a |
hex | 5d7c1272c9 |
401513542345 has 4 divisors (see below), whose sum is σ = 481816250820. Its totient is φ = 321210833872.
The previous prime is 401513542301. The next prime is 401513542361. The reversal of 401513542345 is 543245315104.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 102292508224 + 299221034121 = 319832^2 + 547011^2 .
It is a cyclic number.
It is not a de Polignac number, because 401513542345 - 29 = 401513541833 is a prime.
It is a super-2 number, since 2×4015135423452 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40151354230 + ... + 40151354239.
It is an arithmetic number, because the mean of its divisors is an integer number (120454062705).
Almost surely, 2401513542345 is an apocalyptic number.
It is an amenable number.
401513542345 is a deficient number, since it is larger than the sum of its proper divisors (80302708475).
401513542345 is an equidigital number, since it uses as much as digits as its factorization.
401513542345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80302708474.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 401513542345 its reverse (543245315104), we get a palindrome (944758857449).
The spelling of 401513542345 in words is "four hundred one billion, five hundred thirteen million, five hundred forty-two thousand, three hundred forty-five".
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