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401513542345 = 580302708469
BaseRepresentation
bin1011101011111000001…
…00100111001011001001
31102101101011120021202201
411311330010213023021
523034244431323340
6504241444400201
741002610540626
oct5657404471311
91371334507681
10401513542345
1114530aa22143
12659960a6061
132bb2a092626
141560d1cd34d
15a69e71a79a
hex5d7c1272c9

401513542345 has 4 divisors (see below), whose sum is σ = 481816250820. Its totient is φ = 321210833872.

The previous prime is 401513542301. The next prime is 401513542361. The reversal of 401513542345 is 543245315104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 102292508224 + 299221034121 = 319832^2 + 547011^2 .

It is a cyclic number.

It is not a de Polignac number, because 401513542345 - 29 = 401513541833 is a prime.

It is a super-2 number, since 2×4015135423452 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40151354230 + ... + 40151354239.

It is an arithmetic number, because the mean of its divisors is an integer number (120454062705).

Almost surely, 2401513542345 is an apocalyptic number.

It is an amenable number.

401513542345 is a deficient number, since it is larger than the sum of its proper divisors (80302708475).

401513542345 is an equidigital number, since it uses as much as digits as its factorization.

401513542345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80302708474.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 401513542345 its reverse (543245315104), we get a palindrome (944758857449).

The spelling of 401513542345 in words is "four hundred one billion, five hundred thirteen million, five hundred forty-two thousand, three hundred forty-five".

Divisors: 1 5 80302708469 401513542345