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4015552530013 = 241125831324171
BaseRepresentation
bin111010011011110001100…
…101010000011001011101
3112012212211202112002022021
4322123301211100121131
51011242322421430023
612312415214420141
7563054064222163
oct72336145203135
915185752462267
104015552530013
111308a93799662
1254a2a8501651
13231884c5c70b
14dc4d4ab1233
156e6c156235d
hex3a6f195065d

4015552530013 has 8 divisors (see below), whose sum is σ = 4032538068416. Its totient is φ = 3998569665600.

The previous prime is 4015552529983. The next prime is 4015552530029. The reversal of 4015552530013 is 3100352555104.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4015552530013 is a prime.

It is a super-3 number, since 3×40155525300133 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4015552530043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2370418 + ... + 3694588.

It is an arithmetic number, because the mean of its divisors is an integer number (504067258552).

Almost surely, 24015552530013 is an apocalyptic number.

It is an amenable number.

4015552530013 is a deficient number, since it is larger than the sum of its proper divisors (16985538403).

4015552530013 is a wasteful number, since it uses less digits than its factorization.

4015552530013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1336995.

The product of its (nonzero) digits is 45000, while the sum is 34.

The spelling of 4015552530013 in words is "four trillion, fifteen billion, five hundred fifty-two million, five hundred thirty thousand, thirteen".

Divisors: 1 241 12583 1324171 3032503 319125211 16662043693 4015552530013