40156130041 has 4 divisors (see below), whose sum is σ = 40167610000. Its totient is φ = 40144650084.

The previous prime is 40156130033. The next prime is 40156130093. The reversal of 40156130041 is 14003165104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40156130041 - 2³ = 40156130033 is a prime.

It is a super-2 number, since 2×40156130041² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40156129988 and 40156130015.

It is not an unprimeable number, because it can be changed into a prime (40156130011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5734731 + ... + 5741728.

It is an arithmetic number, because the mean of its divisors is an integer number (10041902500).

Almost surely, 2^40156130041 is an apocalyptic number.

It is an amenable number.

40156130041 is a deficient number, since it is larger than the sum of its proper divisors (11479959).

40156130041 is a wasteful number, since it uses less digits than its factorization.

40156130041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11479958.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 40156130041 its reverse (14003165104), we get a palindrome (54159295145).

The spelling of 40156130041 in words is "forty billion, one hundred fifty-six million, one hundred thirty thousand, forty-one".