4016533511213 has 4 divisors (see below), whose sum is σ = 4016545653120. Its totient is φ = 4016521369308.

The previous prime is 4016533511143. The next prime is 4016533511279. The reversal of 4016533511213 is 3121153356104.

4016533511213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4016533511213 - 2¹⁴ = 4016533494829 is a prime.

It is a super-2 number, since 2×4016533511213² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4016533571213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5560445 + ... + 6241122.

It is an arithmetic number, because the mean of its divisors is an integer number (1004136413280).

Almost surely, 2^{4016533511213} is an apocalyptic number.

It is an amenable number.

4016533511213 is a deficient number, since it is larger than the sum of its proper divisors (12141907).

4016533511213 is a wasteful number, since it uses less digits than its factorization.

4016533511213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12141906.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 4016533511213 its reverse (3121153356104), we get a palindrome (7137686867317).

The spelling of 4016533511213 in words is "four trillion, sixteen billion, five hundred thirty-three million, five hundred eleven thousand, two hundred thirteen".